89 lines
2.5 KiB
Python
89 lines
2.5 KiB
Python
import psycopg2
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conn = psycopg2.connect(
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host="192.168.0.61",
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port=55432,
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database="njts_acct",
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user="njts_app",
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password="njts_app2025"
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)
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cur = conn.cursor()
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print("=" * 120)
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print("【遠達ビル 事務所費用】详细分析")
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print("=" * 120)
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# 查询ID 444和445的journal_lines
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for entry_id in [444, 445]:
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print(f"\n--- 仕訳入力ID={entry_id} ---")
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cur.execute("""
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SELECT
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je.journal_entry_id,
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je.entry_date,
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je.description,
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je.is_latest,
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COUNT(*) as line_count
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FROM journal_entries je
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WHERE je.journal_entry_id = %s
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GROUP BY je.journal_entry_id, je.entry_date, je.description, je.is_latest
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""", (entry_id,))
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je_info = cur.fetchone()
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if je_info:
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entry_id, entry_date, description, is_latest, line_count = je_info
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print(f"日付: {entry_date}")
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print(f"説明: {description}")
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print(f"最新: {is_latest}")
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print(f"明細行数: {line_count}")
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# 取得该仕訳的所有明细行
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cur.execute("""
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SELECT
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jl.journal_line_id,
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jl.account_id,
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a.account_code,
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a.account_name,
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jl.debit,
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jl.credit
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FROM journal_lines jl
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LEFT JOIN accounts a ON jl.account_id = a.account_id
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WHERE jl.journal_entry_id = %s
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ORDER BY jl.journal_line_id
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""", (entry_id,))
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lines = cur.fetchall()
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print(f"\n明細（全{len(lines)}行）:")
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for line_id, acc_id, code, name, debit, credit in lines:
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print(f" Line {line_id}: [{code}] {name} | 借={debit or 0:>10,.0f} 貸={credit or 0:>10,.0f}")
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# 现在检查是否有重复的journal_lines
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print("\n" + "=" * 120)
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print("【重複検出】journal_linesの重复行")
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print("=" * 120)
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cur.execute("""
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SELECT
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journal_entry_id,
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account_id,
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debit,
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credit,
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COUNT(*) as cnt
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FROM journal_lines
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WHERE journal_entry_id IN (444, 445)
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GROUP BY journal_entry_id, account_id, debit, credit
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HAVING COUNT(*) > 1
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""")
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duplicates = cur.fetchall()
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if duplicates:
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print("\n重复検出:")
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for entry_id, acc_id, debit, credit, cnt in duplicates:
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print(f" ID={entry_id}, 科目={acc_id}, 借={debit}, 貸={credit} → {cnt}行重複")
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else:
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print("\n重复行なし")
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cur.close()
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conn.close()
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